import type {TupleToUnion} from 'type-fest';
const destinations = ['a', 'b', 'c'] as const;
type Destination = TupleToUnion<typeof destinations>;
//=> 'a' | 'b' | 'c'
function verifyDestination(destination: unknown): destination is Destination {
return destinations.includes(destination as any);
}
type RequestBody = {
deliverTo: Destination;
};
function verifyRequestBody(body: unknown): body is RequestBody {
const deliverTo = (body as any).deliverTo;
return typeof body === 'object' && body !== null && verifyDestination(deliverTo);
}
Alternatively, you may use typeof destinations[number]
. If destinations
is a tuple, there is no difference. However if destinations
is a string, the resulting type will the union of the characters in the string. Other types of destinations
may result in a compile error. In comparison, TupleToUnion will return never
if a tuple is not provided.
const destinations = ['a', 'b', 'c'] as const;
type Destination = typeof destinations[number];
//=> 'a' | 'b' | 'c'
const erroringType = new Set(['a', 'b', 'c']);
type ErroringType = typeof erroringType[number];
//=> Type 'Set<string>' has no matching index signature for type 'number'. ts(2537)
const numberBool: { [n: number]: boolean } = { 1: true };
type NumberBool = typeof numberBool[number];
//=> boolean
Generated using TypeDoc
Convert a tuple/array into a union type of its elements.
This can be useful when you have a fixed set of allowed values and want a type defining only the allowed values, but do not want to repeat yourself.